50x^2=2240

Solution for 50x^2=2240 equation:

50x^2=2240

We move all terms to the left:

50x^2-(2240)=0

a = 50; b = 0; c = -2240;
Δ = b2-4ac
Δ = 02-4·50·(-2240)
Δ = 448000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{448000}=\sqrt{6400*70}=\sqrt{6400}*\sqrt{70}=80\sqrt{70}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80\sqrt{70}}{2*50}=\frac{0-80\sqrt{70}}{100}
=-\frac{80\sqrt{70}}{100}
=-\frac{4\sqrt{70}}{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80\sqrt{70}}{2*50}=\frac{0+80\sqrt{70}}{100}
=\frac{80\sqrt{70}}{100}
=\frac{4\sqrt{70}}{5}
$